Finite Math Examples

5 x + 0 y = 4

$5 x + 0 y = 4$ ,

0 x + 4 y = - 3

$0 x + 4 y = - 3$

Step 1

Divide each term in

5 x = 4

$5 x = 4$ by

5

$5$ and simplify.

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Step 1.1

Divide each term in

5 x = 4

$5 x = 4$ by

5

$5$ .

\frac{5 x}{5} = \frac{4}{5}

$\frac{5 x}{5} = \frac{4}{5}$

4 y = - 3

$4 y = - 3$

Step 1.2

Simplify the left side.

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Step 1.2.1

Cancel the common factor of

5

$5$ .

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Step 1.2.1.1

Cancel the common factor.

\frac{5 x}{5} = \frac{4}{5}

$\frac{5 x}{5} = \frac{4}{5}$

4 y = - 3

$4 y = - 3$

Step 1.2.1.2

Divide

x

$x$ by

1

$1$ .

x = \frac{4}{5}

$x = \frac{4}{5}$

4 y = - 3

$4 y = - 3$

x = \frac{4}{5}

$x = \frac{4}{5}$

4 y = - 3

$4 y = - 3$

x = \frac{4}{5}

$x = \frac{4}{5}$

4 y = - 3

$4 y = - 3$

x = \frac{4}{5}

$x = \frac{4}{5}$

4 y = - 3

$4 y = - 3$

Step 2

Divide each term in

4 y = - 3

$4 y = - 3$ by

4

$4$ and simplify.

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Step 2.1

Divide each term in

4 y = - 3

$4 y = - 3$ by

4

$4$ .

\frac{4 y}{4} = \frac{- 3}{4}

$\frac{4 y}{4} = \frac{- 3}{4}$

x = \frac{4}{5}

$x = \frac{4}{5}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Cancel the common factor of

4

$4$ .

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Step 2.2.1.1

Cancel the common factor.

\frac{4 y}{4} = \frac{- 3}{4}

$\frac{4 y}{4} = \frac{- 3}{4}$

x = \frac{4}{5}

$x = \frac{4}{5}$

Step 2.2.1.2

Divide

y

$y$ by

1

$1$ .

y = \frac{- 3}{4}

$y = \frac{- 3}{4}$

x = \frac{4}{5}

$x = \frac{4}{5}$

y = \frac{- 3}{4}

$y = \frac{- 3}{4}$

x = \frac{4}{5}

$x = \frac{4}{5}$

y = \frac{- 3}{4}

$y = \frac{- 3}{4}$

x = \frac{4}{5}

$x = \frac{4}{5}$

Step 2.3

Simplify the right side.

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Step 2.3.1

Move the negative in front of the fraction.

y = - \frac{3}{4}

$y = - \frac{3}{4}$

x = \frac{4}{5}

$x = \frac{4}{5}$

y = - \frac{3}{4}

$y = - \frac{3}{4}$

x = \frac{4}{5}

$x = \frac{4}{5}$

y = - \frac{3}{4}

$y = - \frac{3}{4}$

x = \frac{4}{5}

$x = \frac{4}{5}$

Step 3

The solution to the system is the complete set of ordered pairs that are valid solutions.

(\frac{4}{5}, - \frac{3}{4})

$(\frac{4}{5}, - \frac{3}{4})$

Step 4

The result can be shown in multiple forms.

Point Form:

(\frac{4}{5}, - \frac{3}{4})

$(\frac{4}{5}, - \frac{3}{4})$

Equation Form:

x = \frac{4}{5}, y = - \frac{3}{4}

$x = \frac{4}{5}, y = - \frac{3}{4}$

Step 5

5 x + 0 y = 4, 0 x + 4 y = - 3

$5 x + 0 y = 4, 0 x + 4 y = - 3$

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[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$